In: Math
Take the Laplace transform of the following initial value and solve for X(s)=L{x(t)}X(s)=L{x(t)}:
x′′+16x={sin(πt),0}
0≤t<1
1≤t
x(0)=0
x′(0)=0.
a) X(s)=
Now find the inverse transform to find
b) x(t)=
Use u(t−a) for the Heaviside function shifted a units horizontaly.