a solution is prepared by mixing equal masses of methanol, ch3oh, and ethanol, ch3ch2oh what is...

a solution is prepared by mixing equal masses of methanol, ch3oh, and ethanol, ch3ch2oh what is the mole fraction of each component in the mixture

Expert Solution

mass of CH3OH is X

no of moles of CH3OH n1 = X/32

mass of CH3-CH2-OH is X

no of moles of CH3-CH2-OH n2 = X/46

Total no of moles = n1+ n2

= X/32+ X/46 = 46X+ 32X/1472

= 78X/1472 = 0.053X

mole fraction of CH3OH = n1/n1+n2

= X/32/0.053X

= 0.59

mole fraction of CH3OH+ mole fraction of CH3-CH2-OH = 1

mole fraction of CH3-CH2-OH = 1-0.59 = 0.41

queen_honey_blossom answered 2 years ago

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