Question
In: Chemistry
Calculate the molality of a solution that is prepared by mixing 25.5 mL of CH3OH (d...
Calculate the molality of a solution that is prepared by mixing 25.5 mL of CH3OH (d = 0.792 g/mL) and 387 mL of CH3CH2CH2OH (d = 0.811 g/mL). I get 2.01m, but I am not sure if I am doing this right.
Solutions
Expert Solution
mass of CH3OH = volume*density
= 25.5*0.792
= 20.196gm
mass of CH3CH2CH2OH = volume * density
= 387*0.811
= 313.857 gm it is solvent because greater amount
molality = mass of CH3OH*1000/gram molar mass * weight of solvent in gm
= 20.196*1000/32*313.857
= 20196/10043.424
= 2.01m >>>> answer
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