Question

What is the concentration in % (v/v) of a methanol solution prepared by mixing 35.0 mL of methanol with 700 mL of distilled water?

Answer 1

Answer – We are given volume of methanol = 35.0 mL , volume of water = 700 mL .

We need to calculate the concentration in % (v/v) of a methanol solution

First we need to calculate the volume of solution

We know ,

Volume of solution = volume of solute + volume of solvent

                                = 35.0 mL + 700 mL

                                 = 735 mL

We know

concentration in % (v/v) of a methanol = volume of methanol / total volume of solution * 100 %

                                                               = 35.0 mL / 735 mL *100 %

                                                               = 4.76 %