Consider the 2nd order NHDE below d2xdt2+k2x=F0eωt With the following initial conditions x0=0 and x'0=0....

Consider the 2^nd order NHDE below

d2xdt2+k2x=F0eωt

With the following initial conditions x0=0 and x'0=0. (Assume k≠ω)

Find the complimentary solution yc(t)

Find the particular solution yp(t)

Find the general solution for the IVP.

Expert Solution

please note that here in question equation is given in x(t) and solution ask in y(t) which is not possible so I correct the given NHDE and intial conditions in y(t). If you have any doubt in this question then please tell me in comment otherwise like my solution.

milcah answered 2 years ago

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Question

Consider the 2nd order NHDE below d2xdt2+k2x=F0eωt With the following initial conditions x0=0 and x'0=0....

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