In: Chemistry
LiOH(s) + CO2(g) → Li2CO3(s) + H2O(l) If 92.4 grams of lithium hydroxide reacts with excess carbon dioxide, what mass of lithium carbonate will be produced?
The balanced equation is 2LiOH(s) + CO2(g) → Li2CO3(s) + H2O(l)
Molar mass of LiOH = At.mass of Li + At.mass of O + At.mass of H
= 7+16+1
= 24 g/mol
Molar mass of Li2CO3 = (2xAt.mass of Li) + At.mass of C + (3xAt.mass of O)
= (2x7) + 12 + (3x16)
= 74 g/mol
According to the balanced equation ,
2 mole of LiOH produces 1 mole of Li2CO3
OR
2x24 g of LiOH produces 1x74 g of Li2CO3
92.4 g of LiOH produces M g of Li2CO3
M = ( 1x74x92.4) / (2x24)
= 142.45 g
Therefore the mass of lithium carbonate produced is 142.45 g