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LiOH(s) + CO2(g) → Li2CO3(s) + H2O(l) If 92.4 grams of lithium hydroxide reacts with excess...

LiOH(s) + CO2(g) → Li2CO3(s) + H2O(l) If 92.4 grams of lithium hydroxide reacts with excess carbon dioxide, what mass of lithium carbonate will be produced?

Solutions

Expert Solution

The balanced equation is     2LiOH(s) + CO2(g) → Li2CO3(s) + H2O(l)

Molar mass of LiOH = At.mass of Li + At.mass of O + At.mass of H

                              = 7+16+1

                             = 24 g/mol

Molar mass of Li2CO3 = (2xAt.mass of Li) + At.mass of C + (3xAt.mass of O)

                                 = (2x7) + 12 + (3x16)

                                 = 74 g/mol

According to the balanced equation ,

2 mole of LiOH produces 1 mole of Li2CO3

                             OR

2x24 g of LiOH produces 1x74 g of Li2CO3

92.4 g of LiOH produces M g of Li2CO3

M = ( 1x74x92.4) / (2x24)

    = 142.45 g

Therefore the mass of lithium carbonate produced is 142.45 g


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