Question

In: Physics

Two blocks (m1=3kg, m2=7.8kg ) are connected by a string that passes through a massless pulley...

Two blocks (m₁₌3kg, m₂₌7.8kg ) are connected by a string that passes through a massless pulley as shown in the Figure. The first block with mass m₁ slides up the inclined plane when the system is released. The inclined plane makes an angle θ = 22⁰ with the horizontal and the kinetic friction coefficient between the inclined plane and m₁ is =0.49. Take g=10m/s² Find the speed of the block with mass m₂ after it travels h=5.8m.

Expert Solution

First, find the acceleration of the blocks.

Refer the figure

is the frictional force on block m1

is the normal force on block m1

is the tension in the string

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Points to remember:

Frictional force = Coefficient of friction*Normal force.

Weight of block m1, is acting vertically downwards and it can be split into its components.

============

Consider block m1

Net Force = Mass*acceleration

------------(1)

===============================

Consider block m2

Net Force = Mass*Acceleration

Put (1) in the above equation

===================

Consider block m2

The blocks are released from rest, so the initial velocity is zero.

Use formula

ANSWER:

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genius_generous answered 2 years ago

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