Exact Differential Equations: (3x^2 y^2 - 3y^2) dx + (2x^3y - 6xy + 3y^2) dy =...

Exact Differential Equations:

(3x^2 y^2 - 3y^2) dx + (2x^3y - 6xy + 3y^2) dy = 0

Expert Solution

Colby Messinger answered 2 years ago

Integrate the following differential equations: a.) y(2x−y+2)dx+2(x−y)dy = 0; b.) yV-2yIV+3y''' - 2y'' = -x + ex.

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Initial value problem : Differential equations: dx/dt = x + 2y dy/dt = 2x + y...

Initial value problem : Differential equations: dx/dt = x + 2y dy/dt = 2x + y Initial conditions: x(0) = 0 y(0) = 2 a) Find the solution to this initial value problem (yes, I know, the text says that the solutions are x(t)= e^3t - e^-t and y(x) = e^3t + e^-t and but I want you to derive these solutions yourself using one of the methods we studied in chapter 4) Work this part out on paper to...

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Let Q1=y(2) Q2 =y(3) where y=y(x) solves y'+2xy=2x^3 y(0)=1 dy/dx= (2x-y)/(x+4y) y(1)=1 y'+ycotx=y^3sin^3x y(pi/2)=1 (y^2-2x)dx+2xy dy=0 ...

Let Q1=y(2) Q2 =y(3) where y=y(x) solves y'+2xy=2x^3 y(0)=1 dy/dx= (2x-y)/(x+4y) y(1)=1 y'+ycotx=y^3sin^3x y(pi/2)=1 (y^2-2x)dx+2xy dy=0 y(1)=1 2x^2y;+4xy=3sinx y(2pi)=0 y"+2y^-1 (y')^2=y'

given y1 find y2 (Differential Equations) (3x-1)y''-(3x+2)y'-(6x-8)y=0 and y1=e^(2x)

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Exact Differential Equations: (3x^2 y^2 - 3y^2) dx + (2x^3y - 6xy + 3y^2) dy =...

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