d^2y/dx^2 − dy/dx − 3/4 y = 0,
y(0) = 1, dy/dx(0) = 0,
Convert the initial value problem into a set of two coupled
first-order initial value problems
and find the exact solution to the differential equatiion
Solve the following differential equations.
i) y'''-6y''+10y'=0
ii) dy/dx= x2/(1+y2) with y(1)=3
iii) (x2-2y)y'+2x+2xy=0
iv) Use substitution to solve t2y'+2ty=y5
for t>0
Evaluate or solve the following
A) dy/dx=
-(2x2+y2)/(2xy+3y2)
B)dy/dx=(1+y2)/(1+x2)xy
C) (x2+1)dy/dx+2xy=4x2 given that when
x=3,y=4
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