A Circuit board needs to be covered with a layer of gold 5.00 um thick. The...

A Circuit board needs to be covered with a layer of gold 5.00 um thick. The radius of gold atom is 144 picometers(pm). How many gold atoms would be lined up to form this thickness? What is the mass?

Solutions

Expert Solution

Thick ness of layer = 5 * 10^-6 m

diameter of Gold = 2 * 144 *10 ^-12 m

= 288 *10^-12 m

number of gold atoms = (5 * 10^-6) / (288 * 10^-12)

= 17361.11 atoms

6.023 * 10^23 gold atoms mass = 197 g

17361.11 atoms mass = (197/(6.023 *10^23)) * 17361.11

= 5.678 *10^-18 g

queen_honey_blossom answered 1 year ago

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