At 473 K, for the elementary reaction: 2NOCl(g)k1⇌k22NO(g)+Cl2(g) k1=7.8×10−2L/mol⋅s and k2=4.7×102L2/mol2⋅s A sample of NOCl is...

At 473 K, for the elementary reaction:

2NOCl(g)k1⇌k22NO(g)+Cl2(g)

k1=7.8×10−2L/mol⋅s and
k2=4.7×102L2/mol2⋅s

A sample of NOCl is placed in a container and heated to 473 K. When the system comes to equilibrium, [NOCl] is 0.24 mol/L.

Find the concentration of NO.

Find the concentration of Cl2

Solutions

Expert Solution

k = k1 / k2

= 7.8 x 10^-2 / 4.7 x 10^2

= 1.66 x 10^-4

2 NOCl (g) ---------------> 2 NO (g) + Cl2 (g)

a 0 0

a - 2x 2x x

At equilibrium :

NOCl = 0.24

a - 2x = 0.24

K = [NO]^2[Cl2] / [NOCl]^2

1.66 x 10^-4 = (2x)^2 * x / (0.24)^2

x = 0.0134

concentration of NO = 0.027 M

concentration of Cl2 = 0.013 M

queen_honey_blossom answered 1 year ago

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