In: Chemistry
2 NO(g) + Cl2(g) ⇄ 2 NOCl(g) Kp = 1.40 × 10^8 A reaction vessel initially contains 3.0 atm of NO and 2.0 atm of Cl2. What is the pressure of Cl2(g) when equilibrium is reached?
2 NO(g) + Cl2(g) ⇄ 2 NOCl(g)
I 3 2 0
C -2x -x 2x
E 3-2x 2-x 2x
Kp = P^2NOCl/P^2NOPCl2
1.4*10^8 = (2x)^2/(3-2x)^2(2-x)
1.4*10^8 *(3-2x)^2*(2-x) = 4x^2
x = 1.499
PNO = 3-2x = 3-2*1.499 = 0.002atm
PCl2 = 2-x = 2-1.499 = 0.501atm >>>>answer
PNOCl = 2x = 2*1.499 = 3atm