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In: Chemistry

  2 NO(g) + Cl2(g) ⇄ 2 NOCl(g)    Kp = 1.40 × 10^8 A reaction vessel initially...

  2 NO(g) + Cl2(g) ⇄ 2 NOCl(g)    Kp = 1.40 × 10^8 A reaction vessel initially contains 3.0 atm of NO and 2.0 atm of Cl2. What is the pressure of Cl2(g) when equilibrium is reached?

Solutions

Expert Solution

             2 NO(g) + Cl2(g) ⇄ 2 NOCl(g)

I            3                2                0

C            -2x            -x    2x

E 3-2x 2-x 2x

Kp = P^2NOCl/P^2NOPCl2

   1.4*10^8 = (2x)^2/(3-2x)^2(2-x)

1.4*10^8 *(3-2x)^2*(2-x) = 4x^2

      x   = 1.499

   PNO = 3-2x = 3-2*1.499   = 0.002atm

PCl2   = 2-x    = 2-1.499       = 0.501atm >>>>answer

   PNOCl = 2x   = 2*1.499      = 3atm

  


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