Determine the amount of heat (in kJ) given off when 1.38 X 104 g of NO2...

Determine the amount of heat (in kJ) given off when 1.38 X 10⁴ g of NO₂ is produced according to the following equation: 2 NO(g) + O₂ goes to 2NO₂ (g) Delta H = -114.6 kJ/mol Enter your answer in scientific notation

Expert Solution

when 2 mol of NO2 is produced, heat released = 114.6 KJ
molar mass of NO2 = 46 g/mol
2 mol of NO2 = 2*46 = 92 g

When 92 g of NO2 is produced, heat released = 114.6 KJ
when 1.38*10^4 g is produced, heat released = 114.6*1.38*10^4 / 92
= 17190 KJ
= 1.719*10^4 KJ
Answer: 1.719*10^4 KJ = 1.719*10^7 J

queen_honey_blossom answered 1 day ago

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