Assume you wanted to end up with 38.0 g of copper from the reaction below. What...

Assume you wanted to end up with 38.0 g of copper from the reaction below. What mass of copper (II) sulfate would be required?

Fe + CuSO₄-------> Cu + FeSO₄

Expert Solution

Mass of Cu = 28 g

Molar mass of Cu = 63.5 g/mol

Number of moles of Cu formed = mass/molar mass

= 28/63.5

=0.441 mol

So, moles of CuSO4 required = 0.441 mol

Molar mass of CuSO4 =159.5 g/mol

Mass of CuSO4 required =number of moles * molar mass

= 0.441*159.5

=70.33 g

Answer: 70.33 g

queen_honey_blossom answered 3 hours ago

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