Question

In: Statistics and Probability

In the computer game World of Warcraft, some of the strikes are critical strikes, which do...

In the computer game World of Warcraft, some of the strikes are critical strikes, which do more damage. Assume that the probability of a critical strike is the same for every attack, and that attacks are independent. During a particular fight, a character has 261 critical strikes out of 721 attacks. What is the lower bound for the 99% confidence interval for the proportion of strikes that are critical strikes.

Round to three decimal places (for example: 0.419). Write only a number as your answer.

Solutions

Expert Solution

Solution :

Given that,

n = 721

x = 261

= x / n =261 /721 = 0.362

1 - = 1 - 0.362 = 0.638

At 99% confidence level the z is ,

  = 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

Z/2 = Z0.005 = 2.576

Margin of error = E = Z / 2 * (( * (1 - )) / n)

= 2.576 * (((0.362 * 0.638) / 721) = 0.046

A 99 % confidence interval for population proportion p is ,

- E < P < + E

0.362 - 0.046 < p < 0.362 + 0.046

0.316< p <0.408

The 99% confidence interval for the population proportion p is : ( 0.316 , 0.408)

orchestra answered 2 years ago
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