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A tiny ball (mass = 0.043 kg) carries a charge of -18.4

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tiny ball (mass = 0.012 kg) carries a charge of -18 ?C. What electric field (magnitude and direction) is needed to cause the ball to float above the ground?

Given

Mass of the tiny ball m = 0.012kg

charge q = -18*10^-6C

Acceleration due to gravity g = 9.8m/s²

---------------------------------------------------------

We have the formula for the force is

F = qE

but F = mg

mg = qE

The magnitude of the electric field is given by

E = (mg)/q

= (0.012 kg)( 9.8 m/s²)/(18*10^-6C)

Simplifying we get the answer.

genius_generous answered 5 hours ago

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