Question

In: Math

A researcher surveyed 50 local households and found they had their TV’s on an average of...

A researcher surveyed 50 local households and found they had their TV’s on an average of 47.3 hours in a week.   Assume the time Americans have their TV’s turned on is normally distributed with a standard deviation of 6.2 hours.

Construct a 95% confidence interval estimate for the mean time Americans have their TVs turned on in a week.

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Expert Solution

We have given that,                              
                              
Sample mean =47.3 hours                      
Population standard deviation=6.2 hours                  
Sample size=50                      
Level of significance =1-0.95=0.05                      
Z critical value (by using Z table)=1.96                      
                              
Confidence interval formula is


=(45.58 , 49.02)                          
                              


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