In: Statistics and Probability
A researcher had conducted an ANOVA and found that at least one of the following methods of studying for an exam:
1) office hours regularly,
2) both office hours and review sessions,
3) just review sessions, and
4) neither office hours nor review sessions.
differed significantly from the other methods in terms of stats exam scores [F(3, 16) = 9.84, p< .05]. Below is the original ANOVA source table:
Source SS DF MS F
Between 85 3 28.33 9.84
Within 46 16 2.88
The researcher wanted to conduct pairwise comparisons to find which of the methods differed from the others in resulting stats exam scores. The researcher’s raw data were as follows:
Office (O) |
Office & Review (O&R) |
Review (R) |
None (N) |
12 |
12 |
8 |
6 |
11 |
10 |
7 |
9 |
14 |
15 |
10 |
11 |
11 |
14 |
9 |
10 |
12 |
14 |
6 |
9 |
X̄=12 SS=6 |
X̄=13 SS=16 |
X̄=8 SS=10 |
X̄=9 SS=14 |
Conduct pairwise comparisons via both Tukey’s HSD and Scheffe’s test. Show all work
SOLUTION
(1) Ho: All four groups have the same mean (μ1 = μ2 = μ3 = μ4)
Ha: At least two of the four groups have significantly different means
(2) α = 0.05, dfB = 4 - 1 = 3, dfT = 20 - 1 = 19, dfW = 19 - 3 = 16
(3 and 4)