In my hydrolysis lab, I had to add a few drops of 6M of NaOH into...

In my hydrolysis lab, I had to add a few drops of 6M of NaOH into the .1M Fe(NO₃)₃ and it turned solid orange. What formula would come from that observation? Then I had to add 5mL of 6M NaOH into same solution and it was still solid orange but just more because of more NaOH added. What formula would come out of this?

Also in my hydroylis lab I had to add a few drops of 6 M NaOH into .1M AlCl₃ and it turned into a solid. What would be the formula for this? After that I added 5 mL of the 6 M NaOH into the same solution and it dissolved and was clear. What formula do I write for this?

Expert Solution

Yes, this observations consistent with Le Chatelier's Principl. when ever your solution is acidic it shows yellow that means the above equilibium shifted towards A and when it basic it shifted towards B. due to dillution blue may appear as a purple indeed the basic solution colour is green red color. as for example from your experiment

A3, indicator + (1 drop) 0.1 M NaOH + (2 drops)0.1 M HCl :

(1 drop) 0.1 M NaOH + (2 drops)0.1 M HCl = neutral

but remaining (1 drops)0.1 M HCl makes the solution acidic so, it became yellow.

queen_honey_blossom answered 2 hours ago

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