In: Statistics and Probability
The variance in a production process is an important measure of the quality of the process. A large variance often signals an opportunity for improvement in the process by finding ways to reduce the process variance.
2.95 | 3.45 | 3.50 | 3.75 | 3.48 | 3.26 | 3.33 | 3.20 |
3.16 | 3.20 | 3.22 | 3.38 | 3.90 | 3.36 | 3.25 | 3.28 |
3.20 | 3.22 | 2.98 | 3.45 | 3.70 | 3.34 | 3.18 | 3.35 |
3.12 |
3.22 | 3.30 | 3.34 | 3.28 | 3.29 | 3.25 | 3.30 | 3.27 |
3.37 | 3.34 | 3.35 | 3.19 | 3.35 | 3.05 | 3.36 | 3.28 |
3.30 | 3.28 | 3.30 | 3.20 | 3.16 | 3.33 |
Conduct a statistical test to determine whether there is a significant difference between the variances in the bag weights for two machines. Use a 0.05 level of significance. What is your conclusion?
Find the value of the test statistic. (Round your answer to two decimal places.)
Find the p-value. (Round your answer to four decimal places.)
p-value =
Given data :
Machine 1 : 2.95,3.45,3.5,3.75,3.48,3.26,3.33,3.2,3.16,3.20,3.22,3.38,3.9,3.36,3.25,3.28,3.2,3.22,2.98,3.45,3.7,3.34,3.18,3.35, 3.12
n1=25
Mean of mahine1
Sample std dev Machine 1 :
Degrees of freedom Df n=25-1=24
Machine 2 :
3.22,3.3,3.34,3.28,3.29,3.25,3.3,3.27,3.37,3.34,3.35,3.19,3.35,3.05,3.36,3.28,3.3,3.28,3.3,3.2,3.16,3.33
n2=22
Mean of machine 2 :
Sample std dev Machine 2
Degrees of freedom Df d=22-1=21
Hypothesis:
Test Statistics:
P value : Is the value of the lowets level of
singnificance at which we could reject the Null hypothesis
H0
Using P value approch ,we reject the null hypothesis
P value is == 0.00001 almost zero <0.05
Conclusion and decision :
Result is significant at 0.05 Level of singificance
we reject the null hyputhesis,
There is a sufficient evidence that to conclude that singnifice difference between variances of machine