In: Chemistry
1-The lines observed in H-lamp are parts of Balmer Series. All these lines are due to a transition from various higher n value to a common n. What is this common lower n value for all these lines?
| a-0 |
| b-1 |
| c-2 |
| d-3 |
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Question 2
The bright violet line of Hg lamp has a wavelength of 435.8 nm. What is the energy of the photon associated with this emission line?
| a-4.56*10^-19 J |
| b-4.56*10^-28 J |
| c-6.88*10^14 J |
| d-2.89*10^-31 J |
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Question 3
Given: In Atomic Spectra lab, a student obtained his best-fit line equation to be y = 0.29 x + 46.8 when he plotted his Vernier reading on the y-axis and wavelength in nm on the x-axis.
Question: If the Vernier reading for a line is 229.5, what is the predicted wavelength of this line in nm? (Keep 4 sig figs with one decimal place.)
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Question 4
The only electron in a hydrogen atom moved from n=2 to n=6. What is the wavelength of photon (in nm) being associated with this transition? Use whole numbers of nm without any decimal places, such as "415", "1125".
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Question 5
Which of the following transitions of the only electron in hydrogen atom will emit longest wavelength photon?
| a-n=100 to n=5 |
| b-n=4 to n=2 |
| c-n =2 to n=1 |
| d-n=10 to n=20 |
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Question 6
A student obtained the Rydberg constant to be 2.12*10-18 J. What is the % error of the measurement? Answer as percentage and keep one decimal place.
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Question 7
Which of the following orbitals of O has the lowest energy?choose all the right answer
| a-2s |
| b- | 2p |
| c-3d |
| d-4s |
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Question 8
A 100-mL sample of Pb initially has a concentration of 14.3 ppm. If this sample was diluted to 300 mL, what is the new concentration in ppm? Keep one decimal place for your answer.
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Question 9
Which of the following is directly proportional to the concentration of a solution sample?
| a-intensity of light passing through |
| b-transmittance of light |
| c- | absorbance of light |
| d-extinct coefficient |
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Question 10
When measuring the transmittance of the Fe standard solution, what is used as blank?
| a-DI water |
| b-Tap water |
| c- | Fe standard solution without complexing agent |
| d-DI water with complexing agent |
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Question 11
When intensity of light changes due to sample absorption, which of the following change accordingly?
| a-wavelength |
| b-frenqency |
| c-energy of each photon |
| d-transmittance |
1) 1-The lines observed in H-lamp are parts of Balmer Series. All these lines are due to a transition from various higher n value to a common n. What is this common lower n value for all these lines?
The series are
Lyman, n= 1 to n = 2,3,4....
Balmer n= 2 to n = ,3,..4., 5.
Paschen n= 3 to n = 4,5,6....
Brackett n= 4 to n = 5,6,7...
Pfund n= 5 to n = 6,7,8...
So the common lower value for balmer = 2
2) The bright violet line of Hg lamp has a wavelength of 435.8 nm. What is the energy of the photon associated with this emission line?
E = hc / lambda = hc/ wavelength
h = 6.634 X 10-34 Js
c= 3 X 108 m /s
lambda = 435.8 X 10-10 m
Putting values
E = 6.634 X 10-34 Js X 3 X 108 m /s / 435.8 X 10-10 m
E = 4.567 X 10-19 Joules
3)
Given: In Atomic Spectra lab, a student obtained his best-fit line equation to be y = 0.29 x + 46.8 when he plotted his Vernier reading on the y-axis and wavelength in nm on the x-axis.
Question: If the Vernier reading for a line is 229.5, what is the predicted wavelength of this line in nm? (Keep 4 sig figs with one decimal place.)
Ans: y = 0.29 x + 46.8
y = 229.5
x = ?
229.5 = 0.29x +46.8
x = 630.0
4) Given that
n1 = 2
n2 = 6
We know
1/
= R[ (1/n1)2 - (1/n2)2]
= 1.097X107[1/4 - 1/36]
= 1.097X107[0.25 - 0.028]
= 1.097X107[0.222]
= 0.2435 X107
= 1/0.244X107
= 4.098X10-7 m
= 409.8 nm
5) Which of the following transitions of the only electron in hydrogen atom will emit longest wavelength photon?
Ans: longest wavelength means lowest energy
So energy will lowest when the difference between two energy levels is lowest
n=2 to n=1
6)A student obtained the Rydberg constant to be 2.12*10-18 J. What is the % error of the measurement? Answer as percentage and keep one decimal place.
Percentage error = (Actual value - calculated value) X 100 / actual value = (2.17 - 2.12 ) X 10-18 X 100 / 2.17 X 10-18
Percentage error = 2.3 %
7) Lowest energy " 2s
8)A 100-mL sample of Pb initially has a concentration of 14.3 ppm. If this sample was diluted to 300 mL, what is the new concentration in ppm? Keep one decimal place for your answer.
Ans:
c1 X V1 = c2 X V2
100 X 14.3 = 300 X c2
c2 = 4.77 ppm = 4.8 ppm
9) Absorbance