Question

In: Physics

The wavelengths in the hydrogen spectrum with m = 1 form a series of spectral lines...

The wavelengths in the hydrogen spectrum with m = 1 form a series of spectral lines called the Lyman series. Part A Calculate the wavelength of the first member of the Lyman series. Express your answer to three significant figures and include the appropriate units. λ1λ 1 = nothing nothing Request Answer Part B Calculate the wavelength of the second member of the Lyman series. Express your answer to three significant figures and include the appropriate units. λ2λ 2 = nothing nothing Request Answer Part C Calculate the wavelength of the third member of the Lyman series. Express your answer to three significant figures and include the appropriate units. λ3λ 3 = nothing nothing Request Answer Part D Calculate the wavelength of the fourth member of the Lyman series. Express your answer to three significant figures and include the appropriate units.

Solutions

Expert Solution

For hydrogen atom, 1/=Rh (1/nf2- 1/ni2) where is the wavelength of light emitted, Rh is rydberg constant with value 109737cm-1 , nf is the final principal quantum number( which is equal to 1 in this case) , ni is initial quantum number

part a) for 1st member ni =2

So,1/=109737(1-1/4)=82302.75 cm-1

=> =0.0000121502 cm= 122 nm

part b) for 2nd member ni=3

So,1/=109737(1-1/9)=97544 cm-1

=> =0.0000102517 cm= 103 nm

part c) for 3rd member ni=4

So,1/=109737(1-1/16)=102878.4375 cm-1

=> =0.0000097202 cm=97 nm

part d) for 4th member ni=5

So,1/=109737(1-1/25)=105347.52 cm-1

=> =0.0000094923 cm= 95 nm


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