Question

In: Statistics and Probability

The longest "run" of S's in the sequence SSFSSSSFFS has length 4, corresponding to the S's...

The longest "run" of S's in the sequence SSFSSSSFFS has length 4, corresponding to the S's on the fourth, fifth, sixth, and seventh positions. Consider a binomial experiment with n = 4, and let ybe the length (number of trials) in the longest run of S's. (Round your answers to four decimal places.)

(a) When p = 0.5, the 16 possible outcomes are equally likely. Determine the probability distribution of y in this case (first list all outcomes and the y value for each one).

y p(y)
0
1
2
3
4


Calculate μy.
μy =  

(b) Repeat Part (a) for the case p = 0.7.

y p(y)
0
1
2
3
4


Calculate μy.
μy =  

(c) Let z denote the longest run of either S's or F's. Determine the probability distribution of z when p = 0.5.

z p(z)
1
2
3
4

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