In: Statistics and Probability
The longest "run" of S's in the sequence SSFSSSSFFS has length 4, corresponding to the S's on the fourth, fifth, sixth, and seventh positions. Consider a binomial experiment with n = 4, and let ybe the length (number of trials) in the longest run of S's. (Round your answers to four decimal places.)
(a) When p = 0.5, the 16 possible outcomes are equally likely. Determine the probability distribution of y in this case (first list all outcomes and the y value for each one).
| y | p(y) | 
|---|---|
| 0 | |
| 1 | |
| 2 | |
| 3 | |
| 4 | 
Calculate μy.
μy =  
(b) Repeat Part (a) for the case p = 0.7.
| y | p(y) | 
|---|---|
| 0 | |
| 1 | |
| 2 | |
| 3 | |
| 4 | 
Calculate μy.
μy =  
(c) Let z denote the longest run of either S's or
F's. Determine the probability distribution of z
when p = 0.5.
| z | p(z) | 
|---|---|
| 1 | |
| 2 | |
| 3 | |
| 4 |