In: Statistics and Probability
The longest "run" of S's in the sequence SSFSSSSFFS has length 4, corresponding to the S's on the fourth, fifth, sixth, and seventh positions. Consider a binomial experiment with n = 4, and let ybe the length (number of trials) in the longest run of S's. (Round your answers to four decimal places.)
(a) When p = 0.5, the 16 possible outcomes are equally likely. Determine the probability distribution of y in this case (first list all outcomes and the y value for each one).
y | p(y) |
---|---|
0 | |
1 | |
2 | |
3 | |
4 |
Calculate μy.
μy =
(b) Repeat Part (a) for the case p = 0.7.
y | p(y) |
---|---|
0 | |
1 | |
2 | |
3 | |
4 |
Calculate μy.
μy =
(c) Let z denote the longest run of either S's or
F's. Determine the probability distribution of z
when p = 0.5.
z | p(z) |
---|---|
1 | |
2 | |
3 | |
4 |