In: Physics
How fast, in rpm, would a 130 g , 58-cm-diameter beach ball have to spin to have an angular momentum of 0.15 kg⋅m2/s ? Express your answer using two significant figures.
Mass of the ball =130 g
diameter of the ball = 58 cm
needed angular momentum = 0.15 Kg m 2/s
we know

where L is the angular momentum,
I is moment of inertia
is the angular
frequency.
beach ball here can be considered as a spherical shell
for a spherical shell ,

is
moment of inertia
is
mass = 0.13 Kg
is
radius = 0.29 m
give values we get


Kg m
2
from


Kg m
2 /s
Kg m
2
give values


rad/s
which is 51 rpm
hope this helps , regards