Question

In: Chemistry

Consider these reactions, where M represents a generic metal. 1. 2M(s)+6HCl(aq) >>> 2MCl3(aq)+3H2(g) Delta H1=-752.0 kJ...

Consider these reactions, where M represents a generic metal.

1. 2M(s)+6HCl(aq) >>> 2MCl3(aq)+3H2(g)

Delta H1=-752.0 kJ

2. HCl(g) >>> HCl(aq)

Delta H2= -74.8 kJ

3. H2(g)+Cl2(g) >>> 2HCl(g)

Delta H3= -1845.0 kJ

4. MCl3(s) >>> MCl3(aq)

Delta H4= -347.0 kJ

Use the information above to determine the enthalpy of the following reaction.

2M(s)+3Cl2(g) >>> 2MCl3(s)

Delta H= ?kJ

Expert Solution

1. 2M(s)+6HCl(aq) 2MCl₃(aq)+3H₂(g) ; H₁= -752.0 kJ -----(1)

2. HCl(g) HCl(aq) ; H₂= -74.8 kJ -----(2)

3. H₂(g)+Cl₂(g) 2HCl(g) ; H₃= -1845.0 kJ -----(3)

4. MCl₃(s) MCl₃(aq) ; H₄= -347.0 kJ -----(4)

2M(s)+3Cl₂(g) 2MCl₃(s) ; H= ? -----(5)

Eqn(5) can be obtained from first four equations as follows:

Eqn(5) = Eqn(1) + [6xEqn(2)]+[3xEqn(3)]+[2x reverse of Eqn(4)]

So H = H₁ +[6xH₂]+[3xH₃]+[2x(-H₄)]

= -752 + [6x(-74.8)] + [3x(-1845)] +[2x(-(-347))]

= -6041.8 kJ

queen_honey_blossom answered 1 hour ago

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