Question

In: Chemistry

Consider the equilibrium CH4(g) + H2O(g) <--> CO(g) + 3H2(g), where delta h= 206 KJ. Which...

Consider the equilibrium CH4(g) + H2O(g) <--> CO(g) + 3H2(g), where delta h= 206 KJ. Which of the following disturbances will NOT cause the system to shift to the right to reestablish equilibrium?
A.) The partial pressure of CH4 increases.
B.) The partial pressure of CO decreases.
C.) The volume decreases.
D.) The temperature increases.
E.) All of these will cause the system to shift to the right.

Solutions

Expert Solution

Given equilibrium reaction is CH4(g) + H2O(g) <--> CO(g) + 3H2(g) :delta H= 206 KJ.

According to the Le-Charterlier's principle,

(1) If the temperature is raised, reaction will proceed in the direction in which some heat can destroy (absorbed) so that temperature of the system remains constant.

Thus increase in temperature shifts the equilibrium in the forward direction of those reactions which proceed with absorption of heat (endothermic reactions), and in the back ward direction of those reactions which proceed with the evolution of heat (exothermic reactions)

(2) If the pressure is increased, reaction will takes place in a direction which will bring about lowering f pressure. This implies that the equilibrium will shifts in the direction which produces the smaller no. of gas molecules.

(3)  If the concentration of reactants is increased or product is removed , the reaction will take place in the forward direction. If the concentration of reactants decreases or increasing the concentration of products the reaction will take place in the backward direction.

(4) Catalyst speeds up both forward & backward reactions to the same extent but does not have any effect on Equilibrium point.

(5)---> When the no. of moles of reactants & products are same the addition of inert gas has no effect

    ----> for a reaction at constant pressure ,addition of an inert gas will shifts the equilibrium in the direction in

            which there is increase in the no . of moles of the gases  

A.) The partial pressure of CH4 increases.---> reaction proceeds in forward direction(towards right)
B.) The partial pressure of CO decreases.----> reaction proceeds in forward direction(towards right)
C.) The volume decreases.-----> reaction proceeds in forward direction(towards right)
D.) The temperature increases. ------> reaction proceeds in forward direction(towards right)
So All of these will cause the system to shift to the right.

Therefore option (E) is correct


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