In: Statistics and Probability
The Director of Sales purposefully collected data on two variables. These variables are simply identified as Y and X. Data on these two variables are summarized in the table presented below.
| 
 Variable Y  | 
 Variable X  | 
| 
 24 28 25  | 
 20 26 22  | 
| 
 29 33 24 18 26 30 24 29 19  | 
 28 24 19 24 20 21 24 25 14  | 
The Director approaches the Research Division for a validation of the speculative argument that ρ = 0, in the association involving Y and X. The level of significance is 5%. Is it statistically true that ρ = 0? Show all the different stages of hypothesis testing and your calculations.
:
population correlation coefficient
Null hypothesis : Ho : 
 =0
Alternate hypothesis : H1 : 
Two tailed test:
Test Statistic :

n : Number of pairs of observations : 12

| y | x | xy | ![]()  | 
![]()  | 
|
| 24 | 20 | 480 | 400 | 576 | |
| 28 | 26 | 728 | 676 | 784 | |
| 25 | 22 | 550 | 484 | 625 | |
| 29 | 28 | 812 | 784 | 841 | |
| 33 | 24 | 792 | 576 | 1089 | |
| 24 | 19 | 456 | 361 | 576 | |
| 18 | 24 | 432 | 576 | 324 | |
| 26 | 20 | 520 | 400 | 676 | |
| 30 | 21 | 630 | 441 | 900 | |
| 24 | 24 | 576 | 576 | 576 | |
| 29 | 25 | 725 | 625 | 841 | |
| 19 | 14 | 266 | 196 | 361 | |
| Total |  =309 | 
 =267 | 
 =6967 | 
 =6095 | 
 =8169 | 



r=0.5071

Value of the test statistic : t=1.8606;
Degrees of freedom = n-2 =12-2=10
p-value for two tailed test :

For 12 degrees of freedom
2P(t>1.8606) =2 x 0.0462=0.0924
p-value = 0.0924
Given level of significance : 5% i.e 
=0.02 ;
As p-value :0.0924 >  
:
0.02; Fail to reject the null hypothesis.
There is not enough evidence to conclude that 
 i.e
It is statistically true that 
 =0