A.How many moles of silver carbonate can be made from 50.0 ml of 0.100 M AgNO3...

A.How many moles of silver carbonate can be made from 50.0 ml of 0.100 M AgNO3 and 50.0 ml of 0.100 M Na2CO3 ? B. What is the molarity of the carbonate ions left over? (First find how many moles of carbonate are left over.) C. What is the molarity of the sodium ions in the final solution?.

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Expert Solution

2 AgNO3 (aq) + Na2CO3 (aq) --------> 2 NaNO3 (aq) + Ag2CO3 (s)

number of moles of AgNO3 = 50 * 0.1 /1000 = 5 *10^-3 moles

number of moles of Na2CO3 = 50 * 0.1 /1000 = 5 * 10^-3 moles

2 moles of AgNO3 requires 1 mole of Na2CO3

5 * 10^-3 moles of AgNO3 requires (1/2) * 5 *10^-3 moles of Na2CO3

= 2.5 * 10^-3 moles of Na2CO3

remaining moles of Na2CO3 = 5 *10^-3 - 2.5 *10^-3

= 2.5 * 10^-3

concentration of Na2CO3 = 2.5 *10^-3 * 1000/ (50 +50) = 0.025 mol /L

molarity of CO3 2- ions = 0.025 mol /L

molarity of Na+ ions = 0.025* 2 = 0.05 mol /L

queen_honey_blossom answered 1 year ago

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