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When 150.0 mL of a 0.200 M Ca(NO3)2 (MM = 164.088 g/mol) solution is added to...

When 150.0 mL of a 0.200 M Ca(NO3)2 (MM = 164.088 g/mol) solution is added to 200.0 mL of a 0.150 M K3PO4 (MM = 212.27 g/mol) solution, what mass of calcium phosphate (MM = 310.17 g/mol) will precipitate?

a. 9.31 g

b. 3.10 g

c. 2.91 g

d. 1.40 g

e. 4.65 g

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Expert Solution

queen_honey_blossom answered 2 years ago
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