What is the mass (in grams) of 9.31 × 1024 molecules of methanol (CH3OH)?

Expert Solution

6.023*10^23 molecules of CH3OH is having ...................... 32 gm (1 mole)

9.31*10^24 molecules of CH3OH is having ...................?

= 9.31*10^24 * 32 /6.023*10^23

= 494.6 gm.

the mass of 9.31 × 1024 molecules of methanol (CH3OH) is 494.6 gm.

queen_honey_blossom answered 2 years ago

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