In: Statistics and Probability
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.14.1 parts/million (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 10401040 samples is 4.04.0 ppm. Assume a population standard deviation of 1.21.2. Does the data support the researcher's claim at the 0.020.02 level?
Step 1 of 6: State the null and alternative hypotheses.
Step 2 of 6: Find the value of the test statistic. Round your answer to two decimal places
Step 3 of 6: Specify if the test is one-tailed or two-tailed.
Step 4 of 6: Find the P-value of the test statistic. Round your answer to four decimal places.
Step 5 of 6: Identify the level of significance for the hypothesis test.
Step 6 of 6: Make the decision to reject or fail to reject the null hypothesis.
Solution :
Given that ,
= 4.1
= 4.0
= 1.2
n = 1040
( 1 ) The null and alternative hypothesis is ,
H0 : = 4.0
Ha : > 4.0
( 2 ) This is the right tailed test .
Test statistic = z
= ( - ) / / n
= ( 4.0 - 4.1 ) / 1.2 / 1040
= -2.69
( 3 ) The test statistic = -2.69
p (Z > -2.69 ) = 1 - P ( Z < -2.69 )
= 1 - 0.0036
0.9964
( 4 ) P-value = 0.9964
( 5 ) = 0.02
0.9964 > 0.02
P-value >
( 6 ) Fail to reject the null hypothesis .