In: Statistics and Probability
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.7 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 26 samples is 5.0 ppm with a standard deviation of 0.9. Does the data support the claim at the 0.05 level? Assume the population distribution is approximately normal. Step 4 of 5: Determine the decision rule for rejecting the null hypothesis. Round your answer to three decimal places.
Solution :
The null and alternative hypothesis is ,
H0 : = 4.7
Ha : > 4.7
Test statistic (t) =
= ( - ) / s / n
= (5 - 4.7) / 0.9 / 26
Test statistic = 1.700
P-value = 0.0508
= 0.05
P-value >
Fail to reject the null hypothesis .
There is no sufficient evidence to support the claim.