In: Statistics and Probability
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 6.6 parts/million (ppm). A researcher believes that the current ozone level is at an excess level. The mean of 14 samples is 6.7 ppm with a standard deviation of 1.1. Does the data support the claim at the 0.05 level? Assume the population distribution is approximately normal. Step 1 of 5 : State the null and alternative hypotheses.
Solution :
Given that,
Population mean = = 6.6
Sample mean = = 6.7
Sample standard deviation = s = 1.1
Sample size = n = 14
Level of significance = = 0.05
This is a two tailed test.
The null and alternative hypothesis is,
Ho: 6.6
Ha: 6.6
The test statistics,
t = ( - )/ (s/)
= ( 6.7 - 6.6 ) / ( 1.1 / 14)
= 0.34
p-value = 0.7392 ( using t distribution probability table)
The p-value is p = 0.7392 > 0.05, it is concluded that the null hypothesis is fail to reject.
Conclusion :
It is concluded that the null hypothesis Ho is fail to reject. Therefore, there is not enough evidence to claim that the level of
ozone normally found is 6.6 parts/million (ppm) at 0.05 significance level.