Question

In: Biology

Two pink-flowered azaleas are crossed. The cross produces are 25 pink, 13 white, and 10 lavender-flowered...

Two pink-flowered azaleas are crossed. The cross produces are 25 pink, 13 white, and 10 lavender-flowered plants. The color trait could be monogenic with incomplete dominance (1:2:1) or digenic with epistasis (9:4:3).

What statistical test could you perform to test this hypothesis?

Does this test actually allow you to distinguish between these hypotheses? Explain and show your calculations. Note: A p-value of 0.05 equals 5.99 equals for two degrees of freedom.

Solutions

Expert Solution

What statistical test could you perform to test this hypothesis?

The answer is Chisquare test, if the calcualted chisquare is less than the table value then the hypotheis will be accepted, if the calculated chisqaure value is greater than the table value then the hypothesis will be rejected.

Find the chisquare test:

For 1:2:1 ratio:

Null hypothesis: The observed values are not deviating from the monogenic with incomplete dominance ratio i.e. 1:2:1.

Categories

Pink

White

lavendar

Total

Observed values (O)

25

13

10

48

Exptected Ratio (ER)

1

2

1

4

Exprected Values (E)

12

24

12

Deviation (O-E)

13

-11

-2

D^2

169

121

4

D^2/E

14.08333

5.041667

0.333333

19.45833

X^2

19.45833

Degrees of freedom

3-1=2

Inference: The calculated chisquare value i.e. 19.45 is greater than the table value i.e.5.99 at 2 DF and 0.05 probability, hence the null hypothesis is rejected, which means the monogenic with incomplete dominance is not the reason for this phenomenon.

For 9:4:3 ration:

Null hypothesis: The observed values are not deviating from the digenic with epistasis ratio i.e. 9:4:3.

Categories

Pink

White

lavendar

Total

Observed values (O)

25

13

10

48

Exptected Ratio (ER)

9

4

3

16

Exprected Values (E)

27

12

9

Deviation (O-E)

-2

1

1

D^2

4

1

1

D^2/E

0.148148

0.083333

0.111111

0.342593

X^2

0.342593

Degrees of freedom

3-1=2

Inference: The calculated chisquare value i.e. 0.34 is less than the table value i.e.5.99 at 2 DF and 0.05 probability, hence the null hypothesis is accepted, which means digenic with epistasis interaction is the reason for this phenomenon.

gladiator answered 2 years ago
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