Question

In: Physics

A 29.0-kg block is initially at rest on a horizontal surface. A horizontal force of 76.0...

A 29.0-kg block is initially at rest on a horizontal surface. A horizontal force of 76.0 N is required to set the block in motion, after which a horizontal force of 57.0 N is required to keep the block moving with constant speed.

(a) Find the coefficient of static friction between the block and the surface.

(b) Find the coefficient of kinetic friction between the block and the surface.

Solutions

Expert Solution

Given mass of block,

(a) Find the coefficient of static friction between the block and the surface.

When the block is about to move, frictional force acting is static friction force

Force applied,

Consider the block

Net force = Mass * Acceleration =0

Net Force = 0

(a) ANSWER :

=====================

(b) Find the coefficient of kinetic friction between the block and the surface.

When the block starts moving frictional force acting is kinetic friction force

Since the block is moving with constant speed, acceleration is zero

Net force =Mass * Acceleration =0

Net Force = 0

(b) ANSWER :

=====================

genius_generous answered 51 minutes ago
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