Question

In: Statistics and Probability

The Arizona Highway Patrol wants to estimate what proportion of all drivers exceed the 75 mph...

The Arizona Highway Patrol wants to estimate what proportion of all drivers exceed the 75 mph speed limit on a stretch of Rt. 40 on the Arizona side of the state border with New Mexico. For a sample of 1000 vehicles on a given day, 413 exceeded the speed limit. Based on this sample, construct a 95% confidence interval for the percent of vehicles that exceed the speed limit.

Solutions

Expert Solution

n = sample size = 1000 ( total number of vehicles )

x = number of vehicle who exceeded speed limit = 413

Formula for confidence interval

E = margin of error

Zc= Z critical value for given level of confidence

C = 0.95 ( we converted 95 % in to decimal )

Area = 0.9750

We look for the area 0.9750 inside the body of the table to calculate the z critical value.

We get Z critical value as 1.96

Zc = 1.96

95% confidence interval for the percent of vehicles that exceed the speed limit.

We convert the given confidence interval into percentage.

Final answer

95% confidence interval for the percent of vehicles that exceed the speed limit.

Note if you have Ti - 83 or Ti - 84 calculator

Then follow the path to find the above confidence interval.

Press " STAT " .......> then select " tests " ........> scroll down then select " 1 prop z int "

x = 413

n = 1000

c - level = 0.95

and then press " enter "

Now convert that confidence interval into percentage.

I hope this will help you :)


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