A person is seated in a swivel chair. The moment of inertia around the swivel point...

A person is seated in a swivel chair. The moment of inertia around the swivel point will be about 3.0 kg m2for the person and chair combined. If their "friend" starts to spin them, changing their rate of rotation from 1.5 rad/s to 2.0 rad/s in 2.5 s, the net torque being applied is:
a. 0.60nm
b. 1.1nm
c. 2.4nm
d. 3.8nm
e. none of these

A person is seated in a swivel chair. The moment of inertia around the swivel point will be about 3.0 kg m2for the person and chair combined. If their "friend" starts to spin them, producing an angular acceleration of 4.0 rad/s2 for 5.0 s, the net torque being applied is:
a. 0.75nm

b. 1.3nm
c. 2.4nm
d. 12nm
e. none of these.

A person is seated in a swivel chair. The moment of inertia around the swivel point will be about 3.0 kg m2for the person and chair combined. When spinning at 2.0 rad/s, they will be brought to rest by friction in the bearings which applies a net torque whose magnitude is a constant 1.3 n m. How long will it take for them to stop?

0.51 s
4.6s
5.0s
8.7s
none of these.

Expert Solution

genius_generous answered 3 hours ago

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A person is seated in a swivel chair. The moment of inertia around the swivel point...

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