Consider a particle with initial velocity v? that has magnitude 12.0 m/s and is directed 60.0...

Consider a particle with initial velocity v? that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis.

A) What is the x component v? x of v? ? (Answer in m/s)

B) What is the y component v? y of v? ? (Answer in m/s)

C) Now, consider this applet. Two balls are simultaneously dropped from a height of 5.0 m.How long tg does it take for the balls to reach the ground? Use 10 m/s2 for the magnitude of the acceleration due to gravity.

Expert Solution

a)      cos(?) = adjacent / hypotenuse
        cos(60) = v_x / 12.0m/s
         0.5 =v_x /12.0m/s

Since the particle is moving left, the answer will be negative (we could have also converted the angle to 120 degrees):

v_x = -6.00m/s

b)      sin(?) = opposite / hypotenuse
         sin(60) = v_y/ 12.0m/s
          v_y = 10.4 m/s

c)

y-y₀ = v₀t + 1/2at²

The final y position will be 5m

          (5m)-(0m) = 0(t) + 1/2(10m/s²)t²
   5m = (5m/s²)t²
      1s² = t²

t = 1.0s

genius_generous answered 6 hours ago

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