In: Biology
You are given a food containing 6 g protein per serving (30g),
(1) how much of the food you need to add to 50 ml solution to
make a solution with 500 μg protein/ml ?
(2) If you need a 100 ml of a food solution of 50 μg protein/ml,
how will you prepare such solution from the 500 μg protein/ml
solution?
A food contain 6 g of protein per serving (30 g)
1) We have to calculate the amount of food need to be added to 50ml solution to make a solution with 500 μg/ml.
30 g of food contains 6 g of protein.
Let the amount protein required to be added to 50 ml solution to make a solution of 500 μg protein/ml be X
X = 500 μg protein/ml 50 ml
=> X = 50 * 500 μg protein
=> X = 25000 μg
=> X = 0.25 g
Now, 6g of protein is present in 30g of food.
1 g of protein will be present in 30/6 = 5g of food
0.25 g of protein will be present in 5 * 0.25 g = 1.25 g of food
Thus the amount of food is 1.25 g that is required to be added to 50 ml solution to make a solution of 500 μg protein/ml of solution.
2) From a solution of 500 μg protein/ml we have to prepare a 100 ml of food solution of 50 μg protein/ml.
We know that, M1V1 = M2V2
M1 = Initial concentration ( 500 μg protein/ml)
M2 = Final concentration ( 50 μg protein/ml)
V1 = Initial volume
V2 = Final volume ( 100 ml)
Applying, M1V1 = M2V2
500 * V1 = 50 * 100
V1 = 10 ml
This means we have to add 100 - 10 = 90ml of water in 10 ml of 500 μg protein/ml to make it 100 ml of 50 μg protein/ml.