Question

In: Biology

You are given a food containing 6 g protein per serving (30g), (1) how much of...

You are given a food containing 6 g protein per serving (30g),

(1) how much of the food you need to add to 50 ml solution to make a solution with 500 μg protein/ml ?
(2) If you need a 100 ml of a food solution of 50 μg protein/ml, how will you prepare such solution from the 500 μg protein/ml solution?

Solutions

Expert Solution

A food contain 6 g of protein per serving (30 g)

1) We have to calculate the amount of food need to be added to 50ml solution to make a solution with 500 μg/ml.

30 g of food contains 6 g of protein.

Let the amount protein required to be added to 50 ml solution to make a solution of 500 μg protein/ml be X

X     = 500 μg protein/ml 50 ml

=> X = 50 * 500 μg protein

=> X = 25000 μg

=> X = 0.25 g

Now, 6g of protein is present in 30g of food.

1 g of protein will be present in 30/6 = 5g of food

0.25 g of protein will be present in 5 * 0.25 g = 1.25 g of food

Thus the amount of food is 1.25 g that is required to be added to 50 ml solution to make a solution of 500 μg protein/ml of solution.

2) From a solution of 500 μg protein/ml we have to prepare a 100 ml of food solution of 50 μg protein/ml.

We know that, M1V1 = M2V2

M1 = Initial concentration ( 500 μg protein/ml)

M2 = Final concentration ( 50 μg protein/ml)

V1 = Initial volume

V2 = Final volume ( 100 ml)

Applying, M1V1 = M2V2

500 * V1 = 50 * 100

V1 = 10 ml

This means we have to add 100 - 10 = 90ml of water in 10 ml of 500 μg protein/ml to make it 100 ml of 50 μg protein/ml.


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