Calculate the pH and concentrations of CH3NH2 and CH3NH3 in a 0.0495 M methylamine (CH3NH2) solution....

Calculate the pH and concentrations of CH3NH2 and CH3NH3 in a 0.0495 M methylamine (CH3NH2) solution. The Kb of CH3NH2 = 4.47 × 10-4.

Expert Solution

CH3NH2 + H2O --------------> CH3NH3+ + OH-

0.0495 0 0

0.0495 - x x x

Kb = x^2 / 0.0495 - x

4.47 × 10^-4 = x^2 / 0.0495 - x

x = 4.48 x 10^-3

[OH-] = 0.00448 M

[CH3NH3+] = 0.00448 M

pOH = -log [OH-] = -log (0.00448)

= 2.35

pH = 11.65

queen_honey_blossom answered 2 years ago

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