Calculate the pH of a 0.89 M methylamine solution.

Expert Solution

CH3NH2 + H2O <----------------------> CH3NH3+ + OH-

0.89 0 0 ------------------> initial

0.89-x x x ---------------> equilibrium

Kb = [CH3NH3+][OH-]/[CH3NH2]

Kb = x^2 / 0.89-x

4.2 x 10^-4 =x^2 / 0.89-x

x^ + 4.2 x 10^-4 x - 3.738 x 10^-4 = 0

x = 0.019

x = [OH-] = 0.019 M

pOH = -log [OH-] = -log (0.019) = 1.72

pH + pOH = 14

pH = 12.28

queen_honey_blossom answered 1 year ago

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