Question

In: Statistics and Probability

9.Clinical trials of Oxycoting. Oxycoting is a drug used to treat pain, but it is well...

9.Clinical trials of Oxycoting. Oxycoting is a drug used to treat pain, but it is well known for its addictiveness and danger. In a clinical trial, among subjects treated with Oxycotin, 52 developed nausea and 175 did not develop nausea. Among other subjects given placebos, 5 develop nausea and 40 did not develop nausea. Use a 0.05 significance level to test the claim that the proportion of people that develop nausea is greater among the people that take Oxycoting.

Solutions

Expert Solution

Solution

Here we will use two proprtion z- test

(5) Conclusion

It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that the proportion of people that develop nausea is greater among the people that take Oxycoting, at the 0.05 significance level.


Related Solutions

A certain drug is used to treat asthma. In a clinical trial of the? drug, 26...
A certain drug is used to treat asthma. In a clinical trial of the? drug, 26 of 284 treated subjects experienced headaches? (based on data from the? manufacturer). The accompanying calculator display shows results from a test of the claim that less than 9?% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts? (a) through? (e) below. a. two tailed, right tailed or left...
A certain drug is used to treat asthma. In a clinical trial of the​ drug, 21...
A certain drug is used to treat asthma. In a clinical trial of the​ drug, 21 of 299 treated subjects experienced headaches​ (based on data from the​ manufacturer). At a significance level of 0.05, test the claim that less than 9% of people being treated with the asthma drug experience headaches. Use the P-Value method. Address each of the following questions: Is this a Is this a left tailed, right tailed or two tailed test? Are there any conditions that...
1. A certain drug is used to treat asthma. In a clinical trial of the drug,...
1. A certain drug is used to treat asthma. In a clinical trial of the drug, 25 of 256 treated subjects experienced headaches (based on data from the manufacturer). Use a .01 level of significance to test the claim that less than 11% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution.
A certain drug is used to treat asthma. In a clinical trial of the​ drug, 18...
A certain drug is used to treat asthma. In a clinical trial of the​ drug, 18 of 283 treated subjects experienced headaches​ (based on data from the​ manufacturer). The accompanying calculator display shows results from a test of the claim that less than 11​% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts​ (a) through​ (e) below. ​ 1-PropZTest prop < 0.11 z =...
A certain drug is used to treat asthma. In a clinical trial of the​ drug, 22...
A certain drug is used to treat asthma. In a clinical trial of the​ drug, 22 of 266 treated subjects experienced headaches​ (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 11​% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.01 significance level to complete parts​ (a) through​ (e) below. A. Is the test two-tailed, left-tailed, or...
A certain drug is used to treat asthma. In a clinical trial of the​ drug, 25...
A certain drug is used to treat asthma. In a clinical trial of the​ drug, 25 of 289 treated subjects experienced headaches​ (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 8% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.01 significance level to complete parts​ (a) through​ (e) below. A. Is the test two-tailed, left-tailed, or...
7. A certain drug is used to treat asthma. In a clinical trial of the​ drug,...
7. A certain drug is used to treat asthma. In a clinical trial of the​ drug, 20 of 286 treated subjects experienced headaches​ (based on data from the​ manufacturer). The accompanying calculator display shows results from a test of the claim that less than 12​% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts​ (a) through​ (e) below. a. Is the test​ two-tailed, left-tailed,...
A certain drug is used to treat​ pain, but it is dangerous because it is addictive...
A certain drug is used to treat​ pain, but it is dangerous because it is addictive and can be lethal. In clinical​ trials, 235 subjects were treated with the drug and 49 of them developed nausea. a. Construct a 95​% ​(Wald) confidence interval estimate of the percentage of users of the drug who develop nausea.
Suppose 218subjects are treated with a drug that is used to treat pain and 51 of...
Suppose 218subjects are treated with a drug that is used to treat pain and 51 of them developed nausea. Use a 0.01 significance level to test the claim that more than 20​% of users develop nausea. Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. Upper H0​: p=0.20 Upper H1​: p>0.20 B. Upper H 0: p>0.20 Upper H1​: p=0.20 C. Upper H 0H0​: p= 0.20 Upper H 1H1​: p<0.20 D. Upper H0​: p=0.20 Upper...
Suppose 220 subjects are treated with a drug that is used to treat pain and 54...
Suppose 220 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.10 significance level to test the claim that more than 20?% of users develop nausea.Identify the null and alternative hypotheses for this test. Choose the correct answer below.A.Upper H 0?: p equals 0.20Upper H 1?: p not equals 0.20B.Upper H 0?: p equals 0.20Upper H 1?: p greater than 0.20C.Upper H 0?: p greater than 0.20Upper H 1?:...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT