In: Statistics and Probability
A certain drug is used to treat pain, but it is dangerous because it is addictive and can be lethal. In clinical trials,
235
subjects were treated with the drug and
49
of them developed nausea.
a. Construct a
95%
(Wald) confidence interval estimate of the percentage of users of the drug who develop nausea.
Solution :
Given that,
n = 235
x = 49
Point estimate = sample proportion = = x / n = 49/235=0.209
1 - = 1- 0.209 =0.791
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z 0.025 = 1.96 ( Using z table )
Margin of error = E = Z/2 * ((( * (1 - )) / n)
= 1.96 (((0.209*0.791) /49 )
E = 0.114
A 95% confidence interval is ,
- E < p < + E
0.209-0.114 < p < 0.209+0.114
0.095< p < 0.323