In: Chemistry
An unknown pollutant gas has contaminated one of your samples of Ne(g). You test your Ne sample, at constant T and P and find that it effuses through a balloon 3.87 times more rapidly than a pollutant. What is the molar mass of the pollutant gas?
According to Grahm's law of diffusion, at constant Temperature & pressure the rate is inversily proportional to the squareroot of its molar mass of that gas
For a two case system ,
r' = rate of Ne gas = 3.87 times that of pollutant
r = rate of unknown gas
M' = molar mass of Ne = 20 g / mol
M = Molar mass of unknown gas = ?
Plug the above values we get
20/M = 0.26 2
20 / M = 0.0676
M = 20 / 0.0676
= 295.9 g/mol
Therefore the molar mass of the unknown pollutant gas is 295.9 g/mol