In: Physics
Solution - For an infinitely long wire, B( magnetic field) at a point at distance 0.4 m
= [ U.i / 4.(pi)d ] * ( cosa + cosb )
Here i = 3.5 amperes, U is the permittivity of free space = 4(pi) * 10^-7 , d = 0.4 m
For the wire along the X-axis, angle subtended at origin = 45 degrees.
And at infinity, angle subtended = 0 degrees
Thus, B = 3.5 * 10^-7 / 0.4 * ( cos45 + cos0)
= 0.875 * 10^-6 * ( cos45 + cos0 )
Similarly for the wire along the Y-axis,
B = 0.87 * 10^-6 * (cos45 + cos0)
Now, we see that B due to both the wires would in the same direction, and would algebraically add up.
thus, B (total ) = 3.5 * 10^-6 * ( cos45 + cos0 )
Putting the values of cos45 = 0.707 and cos0 = 1, we get
B = 3.5 * 10^-6 * 1.707
= 5.9745 * 10^-6 Tesla
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