In: Physics
Two masses collide inelastically in two different kind of collisions. In the first collision, mass 1 with a mass of 11 kg is moving at 20.9 m/s in the positive x direction and collides with mass 2 with a mass of 4 kg moving at 11.9 m/s in the positive x direction. In the second collision, mass 1 is moving at 20.9 m/s in the positive x direction and collides with mass 2 moving at 11.9 m/s in the negative x direction. If both collisions take place in a time of 0.36 seconds, how much more average force is exerted on mass 2 by mass 1 in the second collision as opposed to the first collision? Answer in Newtons.