In: Chemistry
At a certain concentration of reactants the rate of appearance of water in the fllowing reaction is .29m/s
4NH3+7O2 > 4NO2 + 6H20
What is the rate of reaction for
O2
NH3
O2
4NH3+7O2 > 4NO2 + 6H20
1/4[NH3]/t =1/7 [O2]/t = 1/4[NO2]/t = 1/6[H2O]/t
1/4[NH3]/t =1/6[H2O]/t
rate of water[H2O]/t = 0.29m/s
1/4[NH3]/t = 1/6*0.29 = 0.048m/s
rate of ammonia[NH3]/t = 0.1`92 m/s
1/7 [O2]/t = 1/6[H2O]/t
1/7 [O2]/t = 1/6*0.29 = 0.048m/s
rate of O2 [O2]/t = 0.336m/s
1/4[NO2]/t = 1/6[H2O]/t
1/4[NO2]/t = 1/6*0.29 = 0.048m/s
[NO2]/t = 0.192m/s