A reaction has and △H°298 = 151 kJ/mol and △S°298 = 286 J /mol K at...

A reaction has and △H°298 = 151 kJ/mol and △S°298 = 286 J /mol K at 298 K. Calculate △G in kJ/mol.

Expert Solution

queen_honey_blossom answered 1 year ago

Consider the following reaction at 298 K: 4Al(s) + 3O2(g) ==> 2Al2O3(s) Delta H= -3351.4 kJ/mol...

Consider the following reaction at 298 K: 4Al(s) + 3O2(g) ==> 2Al2O3(s) Delta H= -3351.4 kJ/mol Calculate: a. Delta Ssystem = _______J/mol*K b. Delta Ssurroundings = _______J/mol*K c. Delta S universe = _________J/mol*K

For the reaction below, Δ S ° = − 269 J/(mol · K) and Δ H...

For the reaction below, Δ S ° = − 269 J/(mol · K) and Δ H ° = − 103.8 kJ/mol. Calculate the equilibrium constant at 25 °C. 3C(s) + 4H_2 (g) -->C_3+ H_8 (g)

For a hypothetical reaction, ΔrHθ = 89.1 kJ/mol and ΔrSθ = 364 J/mol/K. What is the...

For a hypothetical reaction, ΔrHθ = 89.1 kJ/mol and ΔrSθ = 364 J/mol/K. What is the total standard entropy of the reaction, ΔrStotθ, at 343 K?

A.) The standard enthalpy change for the following reaction is 359 kJ at 298 K. PbCl2(s)...

A.) The standard enthalpy change for the following reaction is 359 kJ at 298 K. PbCl2(s) ----> Pb(s) + Cl2(g) ΔH° = 359 kJ What is the standard enthalpy change for this reaction at 298 K? Pb(s) + Cl2(g) ----> PbCl2(s) __________ kJ B.) The standard enthalpy change for the following reaction is -602 kJ at 298 K. Mg(s) + 1/2 O2(g) ----> MgO(s) ΔH° = -602 kJ What is the standard enthalpy change for the reaction at 298 K? 2...

1. A chemical reaction at 304 K has an enthalpy change (delta-H) of -73.9 kJ/mol and...

1. A chemical reaction at 304 K has an enthalpy change (delta-H) of -73.9 kJ/mol and an entropy change (delta-S) of 161.6 kJ/mol. What is its Gibbs energy change, delta-G, in kJ/mol? Give the answer to one decimal place. 2.Use the thermodynamic data in your textbook to determine the temperature below which the following reaction is spontaneous. (Give the temperature in K, to the nearest degree.) 2SO2 (g) + O2 (g) -- 2SO3 (g) 3.What is the delta-G for the...

1)For the reaction NH4Cl(aq)--->NH3(g) + HCl(aq) H° = 86.4 kJ and S° = 79.1 J/K The...

1)For the reaction NH4Cl(aq)--->NH3(g) + HCl(aq) H° = 86.4 kJ and S° = 79.1 J/K The equilibrium constant for this reaction at 325.0 K is . Assume that H° and S° are independent of temperature. 2)For the reaction Fe(s) + 2HCl(aq)--->FeCl2(s) + H2(g) H° = -7.4 kJ and S° = 107.9 J/K The equilibrium constant for this reaction at 279.0 K is ____ Assume that H° and S° are independent of temperature.

Cgas = 1.3 J/g×K Hvap = 38.56 kJ/mol Cliq = 2.3 J/g×K Hfus = 5.02 kJ/mol ...

Cgas = 1.3 J/g×K Hvap = 38.56 kJ/mol Cliq = 2.3 J/g×K Hfus = 5.02 kJ/mol Csolid = 0.97 J/g×K Condensation Temp = 78.0oC Freezing Pt = -114.0oC Calculate the amount of heat required toconvert 92.6 mL of ethanol, C2H6O, from 110.0oC to -98.0oC.

The standard enthalpy change for the following reaction is -170 kJ at 298 K. 2 Cu(s)...

The standard enthalpy change for the following reaction is -170 kJ at 298 K. 2 Cu(s) + 1/2 O2(g) Cu2O(s) ΔH° = -170 kJ What is the standard enthalpy change for the reaction at 298 K? 4 Cu(s) + O2(g) 2 Cu2O(s) A student determines the heat of dissolution of solid cobalt(II) chloride using a coffee-cup calorimeter of negligible heat capacity. When 1.33 g of CoCl2(s) is dissolved in 111.00 g of water, the temperature of the solution increases from...

Consider the reaction: 2 NO2(g) → N2O4(g) Calculate ΔG (in kJ/mol) at 298°K if the equilibrium...

Consider the reaction: 2 NO2(g) → N2O4(g) Calculate ΔG (in kJ/mol) at 298°K if the equilibrium partial pressures of NO2 and N2O4 are 1.337 atm and 0.657 atm, respectively.

Estimate Keq for the following equilibria at 350 K. R = 8.3145 J/(molK). Substance ΔHo(kJ/mol) So(J/(molK))...

Estimate Keq for the following equilibria at 350 K. R = 8.3145 J/(mol*K). Substance ΔHo(kJ/mol) So(J/(mol*K)) SnO2(s) -577.6 49.0 H2(g) 0 130.680 CO(g) -110.5 197.7 Sn(s, white) 0 51.2 H2O(l) -285.83 69.95 Fe(s) 0 27.3 Fe3O4(s) -1118.4 146.4 Correct answer. Correct. SnO2(s) + 2H2(g) ⇄ Sn(s, white) + 2H2O(l) The number of significant digits is set to 2; the tolerance is +/-3% LINK TO TEXT Incorrect answer. Incorrect. 3Fe(s) + 4H2O(l) ⇄ Fe3O4(s) + 4H2(g) Entry field with incorrect answer...

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