Question

In: Statistics and Probability

use the following contingency table a b c total 1 15 30 45 90 2 40...

use the following contingency table

a b c total
1 15 30 45 90
2 40 45 50 135
total 55 75 95 225

a. compute the expected frequency for each cell

b. compute x^2stat. is it significant at a=0.01

Solutions

Expert Solution

Solution:

Here, we have to use chi square test for independence of two categorical variables.

Null hypothesis: H0: Two variables are independent.

Alternative hypothesis: Ha: Two variables are dependent.

We assume level of significance = α = 0.01

Test statistic formula is given as below:

Chi square = ∑[(O – E)^2/E]

Where, O is observed frequencies and E is expected frequencies.

E = row total * column total / Grand total

We are given

Number of rows = r = 2

Number of columns = c = 3

Degrees of freedom = df = (r – 1)*(c – 1) = 1*2 = 2

α = 0.01

Critical value = 9.21034

(by using Chi square table or excel)

Calculation tables for test statistic are given as below:

Observed Frequencies

Column variable

Row variable

a

b

c

Total

1

15

30

45

90

2

40

45

50

135

Total

55

75

95

225

(Part a answer)

Expected Frequencies

Column variable

Row variable

a

b

c

Total

1

22

30

38

90

2

33

45

57

135

Total

55

75

95

225

Calculations

(O - E)

-7

0

7

7

0

-7

(O - E)^2/E

2.227273

0

1.289474

1.484848

0

0.859649

Test Statistic = Chi square = ∑[(O – E)^2/E] = 5.861244

(Part b answer)

χ2 statistic = 5.861244

P-value = 0.053364

(By using Chi square table or excel)

P-value > α = 0.01

So, we do not reject the null hypothesis

This test is not significant at α = 0.01.


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