Question

4 part question :)

1. Balance the following equations: (1 point)

a. Na2CO3 + HCl → NaCl + CO2 + H2O

b. Cl2 + KOH → KCl + KClO3 + HCl

c. Fe(OH)2 + O2 + H2O → Fe(OH)3

d. FeS + HCl → FeCl2 + H2S

Answer 1

1. Balance the following equations: (1 point)

a. Na2CO3 + HCl → NaCl + CO2 + H2O

This is acid base reaction here one mole of Na2CO3 will react with two moles of HCl as

Na₂CO₃ + 2HCl → 2NaCl + CO₂ + H₂O Balanced equation

b. Cl2 + KOH → KCl + KClO3 + HCl

Here we have to balance the equation based on atoms as well as by charge

The two half reactions are

(i) Cl₂ ---> Cl- , balanced will be 2e + Cl₂ ---> 2Cl^-

(ii) Cl₂ ---> ClO₃-

Cl₂ ---> 2ClO₃- [To balance the chlorine atom]

In order to balanced oxygen atom we will add water and hydroxide ions as the reaction is taking place in basic medium.

12OH^- + Cl₂ ---> 2ClO₃- + 6H₂O

Let us balance electrons

12OH^- + Cl₂ ---> 2ClO₃- + 6H₂O + 10e

To balance the two equations we will multiply the first equation by 5

2e + Cl₂ ---> 2Cl^- ] X 5

Overall reaction

12OH^- + 6Cl₂ ---> 2ClO₃- + 6H₂O + 10Cl^-

Or

12KOH + 6Cl₂ ---> 2KClO₃ + 6H₂O + 10KCl

c. Fe(OH)₂ + O₂ + H₂O → Fe(OH)₃

The balanced equation is:

4Fe(OH)₂ + O₂ + 2H₂O → 4Fe(OH)₃

d. FeS + HCl → FeCl2 + H2S

The balanced equation will be

FeS + 2HCl → FeCl₂ + H₂S